(7/4)(19)(w)=532

Solution for (7/4)(19)(w)=532 equation:

(7/4)(19)(w)=532

We move all terms to the left:

(7/4)(19)(w)-(532)=0


Domain of the equation: 4)19w!=0

w!=0/1

w!=0

w∈R


We add all the numbers together, and all the variables

(+7/4)19w-532=0

We multiply parentheses

133w^2-532=0

a = 133; b = 0; c = -532;
Δ = b2-4ac
Δ = 02-4·133·(-532)
Δ = 283024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{283024}=532$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-532}{2*133}=\frac{-532}{266}
=-2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+532}{2*133}=\frac{532}{266}
=2
$