(7/4)(x-1)=(7/8)

Solution for (7/4)(x-1)=(7/8) equation:

(7/4)(x-1)=(7/8)

We move all terms to the left:

(7/4)(x-1)-((7/8))=0


Domain of the equation: 4)(x-1)!=0

x∈R


We add all the numbers together, and all the variables

(+7/4)(x-1)-((+7/8))=0

We multiply parentheses ..

(+7x^2+7/4*-1)-((+7/8))=0

We calculate fractions


7x^2/()+()/()=0

We add all the numbers together, and all the variables

7x^2/()+1=0

We multiply all the terms by the denominator


7x^2+1*()=0

We add all the numbers together, and all the variables

7x^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{14}=0$