(7/4)x+3/4=(-3x+5)/4

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Solution for (7/4)x+3/4=(-3x+5)/4 equation: 



(7/4)x+3/4=(-3x+5)/4

We move all terms to the left:

(7/4)x+3/4-((-3x+5)/4)=0



Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+7/4)x-((-3x+5)/4)+3/4=0

We multiply parentheses

7x^2-((-3x+5)/4)+3/4=0

We calculate fractions


7x^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{14}=0$

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