(7/4)x-1=(7/3)x-4

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Solution for (7/4)x-1=(7/3)x-4 equation: 



(7/4)x-1=(7/3)x-4

We move all terms to the left:

(7/4)x-1-((7/3)x-4)=0



Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3)x-4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+7/4)x-((+7/3)x-4)-1=0

We multiply parentheses

7x^2-((+7/3)x-4)-1=0

We multiply all the terms by the denominator


7x^2*3)x-4)-((-1*3)x-4)+7=0

We add all the numbers together, and all the variables

7x^2*3)x-4)-((-3)x-4)+7=0

Wy multiply elements

21x^3-3)x-4)+7=0

We do not support expression: x^3

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