(7/4*x)-(5/6)-(1/12*x)=0

Solution for (7/4*x)-(5/6)-(1/12*x)=0 equation:

(7/4x)-(5/6)-(1/12x)=0


Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 12x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+7/4x)-(+1/12x)-(+5/6)=0

We get rid of parentheses

7/4x-1/12x-5/6=0

We calculate fractions


(-240x^2)/1728x^2+3024x/1728x^2+(-144x)/1728x^2=0

We multiply all the terms by the denominator


(-240x^2)+3024x+(-144x)=0

We get rid of parentheses

-240x^2+3024x-144x=0

We add all the numbers together, and all the variables

-240x^2+2880x=0

a = -240; b = 2880; c = 0;
Δ = b2-4ac
Δ = 28802-4·(-240)·0
Δ = 8294400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8294400}=2880$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2880)-2880}{2*-240}=\frac{-5760}{-480}
=+12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2880)+2880}{2*-240}=\frac{0}{-480}
=0
$