(7/4x-1)=(2/x+5)

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Solution for (7/4x-1)=(2/x+5) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(7/4)*x-1 = 2/x+5 // - 2/x+5

(7/4)*x-(2/x)-5-1 = 0

(7/4)*x-2*x^-1-5-1 = 0

7/4*x^1-2*x^-1-6*x^0 = 0

(7/4*x^2-6*x^1-2*x^0)/(x^1) = 0 // * x^2

x^1*(7/4*x^2-6*x^1-2*x^0) = 0

x^1

(7/4)*x^2-6*x-2 = 0

(7/4)*x^2-6*x-2 = 0

DELTA = (-6)^2-(-2*4*(7/4))

DELTA = 50

DELTA > 0

x = (50^(1/2)+6)/(2*(7/4)) or x = (6-50^(1/2))/(2*(7/4))

x = 2/7*(5*2^(1/2)+6) or x = 2/7*(6-5*2^(1/2))

x in { 2/7*(6-5*2^(1/2)), 2/7*(5*2^(1/2)+6)} 

x in { 2/7*(6-5*2^(1/2)), 2/7*(5*2^(1/2)+6) }

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