(7/4z-3)=(4/9z)

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Solution for (7/4z-3)=(4/9z) equation: 



(7/4z-3)=(4/9z)

We move all terms to the left:

(7/4z-3)-((4/9z))=0



Domain of the equation: 4z-3)!=0

z∈R





Domain of the equation: 9z))!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(7/4z-3)-((+4/9z))=0

We get rid of parentheses

7/4z-((+4/9z))-3=0

We calculate fractions


63z/36z^2+(-((+4*4z)/36z^2-3=0

We calculate fractions

We do not support ezpression: z^4

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