(7/5)x-1=-(7x-5)

Solution for (7/5)x-1=-(7x-5) equation:

(7/5)x-1=-(7x-5)

We move all terms to the left:

(7/5)x-1-(-(7x-5))=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+7/5)x-(-(7x-5))-1=0

We multiply parentheses

7x^2-(-(7x-5))-1=0


We calculate terms in parentheses: -(-(7x-5)), so:

-(7x-5)

We get rid of parentheses

-7x+5

Back to the equation:

-(-7x+5)


We get rid of parentheses

7x^2+7x-5-1=0

We add all the numbers together, and all the variables

7x^2+7x-6=0

a = 7; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·7·(-6)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{217}}{2*7}=\frac{-7-\sqrt{217}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{217}}{2*7}=\frac{-7+\sqrt{217}}{14}
$