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(7/6)q-3=2q-(12/5)
We move all terms to the left:
(7/6)q-3-(2q-(12/5))=0
Domain of the equation: 6)q!=0We add all the numbers together, and all the variables
q!=0/1
q!=0
q∈R
(+7/6)q-(2q-(+12/5))-3=0
We multiply parentheses
7q^2-(2q-(+12/5))-3=0
We multiply all the terms by the denominator
7q^2*5))-(2q-(+12-3*5))=0
We add all the numbers together, and all the variables
7q^2*5))-(2q-(-3))=0
We add all the numbers together, and all the variables
7q^2*5))-(2q-(=0
Wy multiply elements
35q^3=0
We do not support eqpression: q^3
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