(7/7x+3)=(2/x-3)

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Solution for (7/7x+3)=(2/x-3) equation: 



(7/7x+3)=(2/x-3)

We move all terms to the left:

(7/7x+3)-((2/x-3))=0



Domain of the equation: 7x+3)!=0

x∈R





Domain of the equation: x-3))!=0

x∈R



We get rid of parentheses

7/7x-((2/x-3))+3=0

We calculate fractions


7x/7x^2+(-((2*7x)/7x^2+3=0

We add all the numbers together, and all the variables

7x/7x^2+(-((+2*7x)/7x^2+3=0

We calculate fractions

We do not support expression: x^4

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