(7/8)n-3=(5/8)n+12

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Solution for (7/8)n-3=(5/8)n+12 equation: 



(7/8)n-3=(5/8)n+12

We move all terms to the left:

(7/8)n-3-((5/8)n+12)=0



Domain of the equation: 8)n!=0

n!=0/1

n!=0

n∈R





Domain of the equation: 8)n+12)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

(+7/8)n-((+5/8)n+12)-3=0

We multiply parentheses

7n^2-((+5/8)n+12)-3=0

We multiply all the terms by the denominator


7n^2*8)n+12)-((-3*8)n+12)+5=0

We add all the numbers together, and all the variables

7n^2*8)n+12)-((-24)n+12)+5=0

Wy multiply elements

56n^3-24)n+12)+5=0

We do not support enpression: n^3

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