(7/8)x+(3/4)=-6

Solution for (7/8)x+(3/4)=-6 equation:

(7/8)x+(3/4)=-6

We move all terms to the left:

(7/8)x+(3/4)-(-6)=0


Domain of the equation: 8)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+7/8)x+(+3/4)-(-6)=0

We add all the numbers together, and all the variables

(+7/8)x+6+(+3/4)=0

We multiply parentheses

7x^2+6+(+3/4)=0

We get rid of parentheses

7x^2+6+3/4=0

We multiply all the terms by the denominator


7x^2*4+3+6*4=0

We add all the numbers together, and all the variables

7x^2*4+27=0

Wy multiply elements

28x^2+27=0

a = 28; b = 0; c = +27;
Δ = b2-4ac
Δ = 02-4·28·27
Δ = -3024
Delta is less than zero, so there is no solution for the equation