(7/8)x=9/10

Solution for (7/8)x=9/10 equation:

(7/8)x=9/10

We move all terms to the left:

(7/8)x-(9/10)=0


Domain of the equation: 8)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+7/8)x-(+9/10)=0

We multiply parentheses

7x^2-(+9/10)=0

We get rid of parentheses

7x^2-9/10=0

We multiply all the terms by the denominator


7x^2*10-9=0

Wy multiply elements

70x^2-9=0

a = 70; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·70·(-9)
Δ = 2520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2520}=\sqrt{36*70}=\sqrt{36}*\sqrt{70}=6\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{70}}{2*70}=\frac{0-6\sqrt{70}}{140}
=-\frac{6\sqrt{70}}{140}
=-\frac{3\sqrt{70}}{70}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{70}}{2*70}=\frac{0+6\sqrt{70}}{140}
=\frac{6\sqrt{70}}{140}
=\frac{3\sqrt{70}}{70}
$