(7/x)-(1/3x)=8/3

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Solution for (7/x)-(1/3x)=8/3 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x-((1/3)*x) = 8/3 // - 8/3

7/x-((1/3)*x)-(8/3) = 0

(-1/3)*x+7/x-8/3 = 0

7*x^-1-1/3*x^1-8/3*x^0 = 0

(7*x^0-1/3*x^2-8/3*x^1)/(x^1) = 0 // * x^2

x^1*(7*x^0-1/3*x^2-8/3*x^1) = 0

x^1

(-1/3)*x^2+(-8/3)*x+7 = 0

(-1/3)*x^2+(-8/3)*x+7 = 0

DELTA = (-8/3)^2-(4*7*(-1/3))

DELTA = 148/9

DELTA > 0

x = ((148/9)^(1/2)-(-8/3))/(2*(-1/3)) or x = (-(-8/3)-(148/9)^(1/2))/(2*(-1/3))

x = -3/2*((148/9)^(1/2)+8/3) or x = -3/2*(8/3-(148/9)^(1/2))

x in { -3/2*((148/9)^(1/2)+8/3), -3/2*(8/3-(148/9)^(1/2))}

x in { -3/2*((148/9)^(1/2)+8/3), -3/2*(8/3-(148/9)^(1/2)) }

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