(7/x)=(5/2x)+36

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Solution for (7/x)=(5/2x)+36 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x = (5/2)*x+36 // - (5/2)*x+36

7/x-((5/2)*x)-36 = 0

(-5/2)*x+7/x-36 = 0

7*x^-1-5/2*x^1-36*x^0 = 0

(7*x^0-5/2*x^2-36*x^1)/(x^1) = 0 // * x^2

x^1*(7*x^0-5/2*x^2-36*x^1) = 0

x^1

(-5/2)*x^2-36*x+7 = 0

(-5/2)*x^2-36*x+7 = 0

DELTA = (-36)^2-(4*7*(-5/2))

DELTA = 1366

DELTA > 0

x = (1366^(1/2)+36)/(2*(-5/2)) or x = (36-1366^(1/2))/(2*(-5/2))

x = (1366^(1/2)+36)/(-5) or x = (36-1366^(1/2))/(-5)

x in { (1366^(1/2)+36)/(-5), (36-1366^(1/2))/(-5)}

x in { (1366^(1/2)+36)/(-5), (36-1366^(1/2))/(-5) }

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