(7/x-3)=(8/2x+5)

Solution for (7/x-3)=(8/2x+5) equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7/x-3 = (8/2)*x+5 // - (8/2)*x+5

7/x-((8/2)*x)-5-3 = 0

7/x-4*x-5-3 = 0

7*x^-1-4*x^1-8*x^0 = 0

(7*x^0-4*x^2-8*x^1)/(x^1) = 0 // * x^2

x^1*(7*x^0-4*x^2-8*x^1) = 0

x^1

7-4*x^2-8*x = 0

7-4*x^2-8*x = 0

DELTA = (-8)^2-(-4*4*7)

DELTA = 176

DELTA > 0

x = (176^(1/2)+8)/(-4*2) or x = (8-176^(1/2))/(-4*2)

x = (4*11^(1/2)+8)/(-8) or x = (8-4*11^(1/2))/(-8)

x in { (4*11^(1/2)+8)/(-8), (8-4*11^(1/2))/(-8)} 

x in { (4*11^(1/2)+8)/(-8), (8-4*11^(1/2))/(-8) }