(7/z)-(z/3)

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Solution for (7/z)-(z/3) equation:


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

7/z-(z/3) = 0

7*z^-1-1/3*z^1 = 0

(7*z^0-1/3*z^2)/(z^1) = 0 // * z^2

z^1*(7*z^0-1/3*z^2) = 0

z^1

(-1/3)*z^2+7 = 0

(-1/3)*z^2+7 = 0

DELTA = 0^2-(4*7*(-1/3))

DELTA = 28/3

DELTA > 0

z = ((28/3)^(1/2)+0)/(2*(-1/3)) or z = (0-(28/3)^(1/2))/(2*(-1/3))

z = -3/2*(28/3)^(1/2) or z = 3/2*(28/3)^(1/2)

z in { -3/2*(28/3)^(1/2), 3/2*(28/3)^(1/2)}

z in { -3/2*(28/3)^(1/2), 3/2*(28/3)^(1/2) }

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