(70)+(3x-2)=x

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Solution for (70)+(3x-2)=x equation: 



(70)+(3x-2)=x

We move all terms to the left:

(70)+(3x-2)-(x)=0

We add all the numbers together, and all the variables

-1x+(3x-2)+70=0

We get rid of parentheses

-1x+3x-2+70=0

We add all the numbers together, and all the variables

2x+68=0

We move all terms containing x to the left, all other terms to the right

2x=-68

x=-68/2

x=-34

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