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(70-7x)=(-2x)(-2x)
We move all terms to the left:
(70-7x)-((-2x)(-2x))=0
We add all the numbers together, and all the variables
(-7x+70)-((-2x)(-2x))=0
We get rid of parentheses
-7x-((-2x)(-2x))+70=0
We multiply parentheses ..
-((+4x^2))-7x+70=0
We calculate terms in parentheses: -((+4x^2)), so:a = -4; b = -7; c = +70;
(+4x^2)
We get rid of parentheses
4x^2
Back to the equation:
-(4x^2)
Δ = b2-4ac
Δ = -72-4·(-4)·70
Δ = 1169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{1169}}{2*-4}=\frac{7-\sqrt{1169}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{1169}}{2*-4}=\frac{7+\sqrt{1169}}{-8} $
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