(72+x+(x+1))/3=83

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Solution for (72+x+(x+1))/3=83 equation: 



(72+x+(x+1))/3=83

We move all terms to the left:

(72+x+(x+1))/3-(83)=0

We multiply all the terms by the denominator


(72+x+(x+1))-83*3=0



We calculate terms in parentheses: +(72+x+(x+1)), so:

72+x+(x+1)

determiningTheFunctionDomain
x+(x+1)+72

We get rid of parentheses

x+x+1+72

We add all the numbers together, and all the variables

2x+73

Back to the equation:

+(2x+73)



We add all the numbers together, and all the variables

(2x+73)-249=0

We get rid of parentheses

2x+73-249=0

We add all the numbers together, and all the variables

2x-176=0

We move all terms containing x to the left, all other terms to the right

2x=176

x=176/2

x=88

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