(78)+(3x-12)=(6x+12)

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Solution for (78)+(3x-12)=(6x+12) equation: 



(78)+(3x-12)=(6x+12)

We move all terms to the left:

(78)+(3x-12)-((6x+12))=0

We get rid of parentheses

3x-((6x+12))-12+78=0



We calculate terms in parentheses: -((6x+12)), so:

(6x+12)

We get rid of parentheses

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

3x-(6x+12)+66=0

We get rid of parentheses

3x-6x-12+66=0

We add all the numbers together, and all the variables

-3x+54=0

We move all terms containing x to the left, all other terms to the right

-3x=-54

x=-54/-3

x=+18

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