(78-x)+36+(3x-10)=180

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Solution for (78-x)+36+(3x-10)=180 equation: 



(78-x)+36+(3x-10)=180

We move all terms to the left:

(78-x)+36+(3x-10)-(180)=0

We add all the numbers together, and all the variables

(-1x+78)+(3x-10)+36-180=0

We add all the numbers together, and all the variables

(-1x+78)+(3x-10)-144=0

We get rid of parentheses

-1x+3x+78-10-144=0

We add all the numbers together, and all the variables

2x-76=0

We move all terms containing x to the left, all other terms to the right

2x=76

x=76/2

x=38

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