(79-5x)=(4x+61)

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Solution for (79-5x)=(4x+61) equation: 



(79-5x)=(4x+61)

We move all terms to the left:

(79-5x)-((4x+61))=0

We add all the numbers together, and all the variables

(-5x+79)-((4x+61))=0

We get rid of parentheses

-5x-((4x+61))+79=0



We calculate terms in parentheses: -((4x+61)), so:

(4x+61)

We get rid of parentheses

4x+61

Back to the equation:

-(4x+61)



We get rid of parentheses

-5x-4x-61+79=0

We add all the numbers together, and all the variables

-9x+18=0

We move all terms containing x to the left, all other terms to the right

-9x=-18

x=-18/-9

x=+2

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