(79/10)-(8/10)x=(23/10)

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Solution for (79/10)-(8/10)x=(23/10) equation: 



(79/10)-(8/10)x=(23/10)

We move all terms to the left:

(79/10)-(8/10)x-((23/10))=0



Domain of the equation: 10)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(+8/10)x+(+79/10)-((+23/10))=0

We multiply parentheses

-8x^2+(+79/10)-((+23/10))=0

We get rid of parentheses

-8x^2+79/10-((+23/10))=0

We calculate fractions


-8x^2=0

a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-16}=0$

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