(7I+9)+(4k-3)=0

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Solution for (7I+9)+(4k-3)=0 equation: 



(7+9)+(4I-3)=0

We add all the numbers together, and all the variables

(4I-3)+16=0

We get rid of parentheses

4I-3+16=0

We add all the numbers together, and all the variables

4I+13=0

We move all terms containing I to the left, all other terms to the right

4I=-13

I=-13/4

I=-3+1/4

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