(7Y+3)+(3Y+4)=14y-25

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Solution for (7Y+3)+(3Y+4)=14y-25 equation: 


Simplifying
(7Y + 3) + (3Y + 4) = 14y + -25

Reorder the terms:
(3 + 7Y) + (3Y + 4) = 14y + -25

Remove parenthesis around (3 + 7Y)
3 + 7Y + (3Y + 4) = 14y + -25

Reorder the terms:
3 + 7Y + (4 + 3Y) = 14y + -25

Remove parenthesis around (4 + 3Y)
3 + 7Y + 4 + 3Y = 14y + -25

Reorder the terms:
3 + 4 + 7Y + 3Y = 14y + -25

Combine like terms: 3 + 4 = 7
7 + 7Y + 3Y = 14y + -25

Combine like terms: 7Y + 3Y = 10Y
7 + 10Y = 14y + -25

Reorder the terms:
7 + 10Y = -25 + 14y

Solving
7 + 10Y = -25 + 14y

Solving for variable 'Y'.

Move all terms containing Y to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 10Y = -25 + -7 + 14y

Combine like terms: 7 + -7 = 0
0 + 10Y = -25 + -7 + 14y
10Y = -25 + -7 + 14y

Combine like terms: -25 + -7 = -32
10Y = -32 + 14y

Divide each side by '10'.
Y = -3.2 + 1.4y

Simplifying
Y = -3.2 + 1.4y

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