(7a-5)(8a+7)=(7a-5)(8a)+(7a-5)(7)

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Solution for (7a-5)(8a+7)=(7a-5)(8a)+(7a-5)(7) equation: 



(7a-5)(8a+7)=(7a-5)(8a)+(7a-5)(7)

We move all terms to the left:

(7a-5)(8a+7)-((7a-5)(8a)+(7a-5)(7))=0

We multiply parentheses ..

(+56a^2+49a-40a-35)-((7a-5)8a+(7a-5)7)=0



We calculate terms in parentheses: -((7a-5)8a+(7a-5)7), so:

(7a-5)8a+(7a-5)7

We multiply parentheses

56a^2-40a+49a-35

We add all the numbers together, and all the variables

56a^2+9a-35

Back to the equation:

-(56a^2+9a-35)



We get rid of parentheses

56a^2-56a^2+49a-40a-9a-35+35=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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