(7b)+(9b)+(b+44)=180

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Solution for (7b)+(9b)+(b+44)=180 equation: 



(7b)+(9b)+(b+44)=180

We move all terms to the left:

(7b)+(9b)+(b+44)-(180)=0

We add all the numbers together, and all the variables

16b+(b+44)-180=0

We get rid of parentheses

16b+b+44-180=0

We add all the numbers together, and all the variables

17b-136=0

We move all terms containing b to the left, all other terms to the right

17b=136

b=136/17

b=8

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