(7c+3)/4=(9-5c)/12

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Solution for (7c+3)/4=(9-5c)/12 equation: 


c in (-oo:+oo)

(7*c+3)/4 = (9-(5*c))/12 // - (9-(5*c))/12

(7*c+3)/4-((9-(5*c))/12) = 0

(7*c+3)/4-((9-5*c)/12) = 0

(7*c+3)/4+(-1*(9-5*c))/12 = 0

(12*(7*c+3))/(4*12)+(-1*4*(9-5*c))/(4*12) = 0

12*(7*c+3)-1*4*(9-5*c) = 0

104*c = 0

(104*c)/(4*12) = 0

(104*c)/(4*12) = 0 // * 4*12

104*c = 0

104*c = 0 // : 104

c = 0

c = 0

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