(7h-1)(h-2)=0

Solution for (7h-1)(h-2)=0 equation:

(7h-1)(h-2)=0

We multiply parentheses ..

(+7h^2-14h-1h+2)=0

We get rid of parentheses

7h^2-14h-1h+2=0

We add all the numbers together, and all the variables

7h^2-15h+2=0

a = 7; b = -15; c = +2;
Δ = b2-4ac
Δ = -152-4·7·2
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-13}{2*7}=\frac{2}{14}
=1/7
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+13}{2*7}=\frac{28}{14}
=2
$