(7h-4)(h-8)=

Solution for (7h-4)(h-8)= equation:

(7h-4)(h-8)=

We move all terms to the left:

(7h-4)(h-8)-()=0

We add all the numbers together, and all the variables

(7h-4)(h-8)=0

We multiply parentheses ..

(+7h^2-56h-4h+32)=0

We get rid of parentheses

7h^2-56h-4h+32=0

We add all the numbers together, and all the variables

7h^2-60h+32=0

a = 7; b = -60; c = +32;
Δ = b2-4ac
Δ = -602-4·7·32
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-52}{2*7}=\frac{8}{14}
=4/7
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+52}{2*7}=\frac{112}{14}
=8
$