(7i)(-4i)(1+4i)=

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Solution for (7i)(-4i)(1+4i)= equation:


Simplifying
(7i)(-4i)(1 + 4i) = 0

Remove parenthesis around (7i)
7i(-4i)(1 + 4i) = 0

Remove parenthesis around (-4i)
7i * -4i(1 + 4i) = 0

Reorder the terms for easier multiplication:
7 * -4i * i(1 + 4i) = 0

Multiply 7 * -4
-28i * i(1 + 4i) = 0

Multiply i * i
-28i2(1 + 4i) = 0
(1 * -28i2 + 4i * -28i2) = 0
(-28i2 + -112i3) = 0

Solving
-28i2 + -112i3 = 0

Solving for variable 'i'.

Factor out the Greatest Common Factor (GCF), '-28i2'.
-28i2(1 + 4i) = 0

Ignore the factor -28.

Subproblem 1

Set the factor 'i2' equal to zero and attempt to solve: Simplifying i2 = 0 Solving i2 = 0 Move all terms containing i to the left, all other terms to the right. Simplifying i2 = 0 Take the square root of each side: i = {0}

Subproblem 2

Set the factor '(1 + 4i)' equal to zero and attempt to solve: Simplifying 1 + 4i = 0 Solving 1 + 4i = 0 Move all terms containing i to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 4i = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 4i = 0 + -1 4i = 0 + -1 Combine like terms: 0 + -1 = -1 4i = -1 Divide each side by '4'. i = -0.25 Simplifying i = -0.25

Solution

i = {0, -0.25}

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