(7k-3)/4=(13-5k)/8

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Solution for (7k-3)/4=(13-5k)/8 equation: 



(7k-3)/4=(13-5k)/8

We move all terms to the left:

(7k-3)/4-((13-5k)/8)=0

We add all the numbers together, and all the variables

(7k-3)/4-((-5k+13)/8)=0

We calculate fractions


7k/()+(-((-5k+13)*4)/()=0



We calculate terms in parentheses: +(-((-5k+13)*4)/(), so:

-((-5k+13)*4)/(

We multiply all the terms by the denominator


-((-5k+13)*4)



We calculate terms in parentheses: -((-5k+13)*4), so:

(-5k+13)*4

We multiply parentheses

-20k+52

Back to the equation:

-(-20k+52)



We get rid of parentheses

20k-52

Back to the equation:

+(20k-52)



We get rid of parentheses

7k/()+20k-52=0

We multiply all the terms by the denominator


7k+20k*()-52*()=0

We add all the numbers together, and all the variables

7k+20k*()=0

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