(7m)/(3m+3)-5=((3)/2m)

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Solution for (7m)/(3m+3)-5=((3)/2m) equation:


D( m )

3*m+3 = 0

3*m+3 = 0

3*m+3 = 0

3*m+3 = 0 // - 3

3*m = -3 // : 3

m = -3/3

m = -1

m in (-oo:-1) U (-1:+oo)

(7*m)/(3*m+3)-5 = (3/2)*m // - (3/2)*m

(7*m)/(3*m+3)-((3/2)*m)-5 = 0

(7*m)/(3*m+3)+(-3/2)*m-5 = 0

(7*m)/(3*m+3)+(-3*m)/2-5 = 0

(2*7*m)/(2*(3*m+3))+(-3*m*(3*m+3))/(2*(3*m+3))+(-5*2*(3*m+3))/(2*(3*m+3)) = 0

2*7*m-3*m*(3*m+3)-5*2*(3*m+3) = 0

5*m-9*m^2-30*m-30 = 0

-9*m^2-25*m-30 = 0

-9*m^2-25*m-30 = 0

-1*(9*m^2+25*m+30) = 0

9*m^2+25*m+30 = 0

DELTA = 25^2-(4*9*30)

DELTA = -455

DELTA < 0

-1 = 0

-1/(2*(3*m+3)) = 0

-1/(2*(3*m+3)) = 0 // * 2*(3*m+3)

-1 = 0

m belongs to the empty set

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