(7m+12)/8=(2m-1)/3

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Solution for (7m+12)/8=(2m-1)/3 equation: 



(7m+12)/8=(2m-1)/3

We move all terms to the left:

(7m+12)/8-((2m-1)/3)=0

We calculate fractions


7m/()+(-((2m-1)*8)/()=0



We calculate terms in parentheses: +(-((2m-1)*8)/(), so:

-((2m-1)*8)/(

We multiply all the terms by the denominator


-((2m-1)*8)



We calculate terms in parentheses: -((2m-1)*8), so:

(2m-1)*8

We multiply parentheses

16m-8

Back to the equation:

-(16m-8)



We get rid of parentheses

-16m+8

Back to the equation:

+(-16m+8)



We get rid of parentheses

7m/()-16m+8=0

We multiply all the terms by the denominator


7m-16m*()+8*()=0

We add all the numbers together, and all the variables

7m-16m*()=0

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