(7p+2)(8p+1)=0

Solution for (7p+2)(8p+1)=0 equation:

(7p+2)(8p+1)=0

We multiply parentheses ..

(+56p^2+7p+16p+2)=0

We get rid of parentheses

56p^2+7p+16p+2=0

We add all the numbers together, and all the variables

56p^2+23p+2=0

a = 56; b = 23; c = +2;
Δ = b2-4ac
Δ = 232-4·56·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-9}{2*56}=\frac{-32}{112}
=-2/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+9}{2*56}=\frac{-14}{112}
=-1/8
$