(7p-1)(p-7)=0

Solution for (7p-1)(p-7)=0 equation:

(7p-1)(p-7)=0

We multiply parentheses ..

(+7p^2-49p-1p+7)=0

We get rid of parentheses

7p^2-49p-1p+7=0

We add all the numbers together, and all the variables

7p^2-50p+7=0

a = 7; b = -50; c = +7;
Δ = b2-4ac
Δ = -502-4·7·7
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-48}{2*7}=\frac{2}{14}
=1/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+48}{2*7}=\frac{98}{14}
=7
$