(7q+2z)+(q+5z)=

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Solution for (7q+2z)+(q+5z)= equation:


Simplifying
(7q + 2z) + (q + 5z) = 0

Remove parenthesis around (7q + 2z)
7q + 2z + (q + 5z) = 0

Remove parenthesis around (q + 5z)
7q + 2z + q + 5z = 0

Reorder the terms:
7q + q + 2z + 5z = 0

Combine like terms: 7q + q = 8q
8q + 2z + 5z = 0

Combine like terms: 2z + 5z = 7z
8q + 7z = 0

Solving
8q + 7z = 0

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-7z' to each side of the equation.
8q + 7z + -7z = 0 + -7z

Combine like terms: 7z + -7z = 0
8q + 0 = 0 + -7z
8q = 0 + -7z
Remove the zero:
8q = -7z

Divide each side by '8'.
q = -0.875z

Simplifying
q = -0.875z

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