(7r-2/3)-(2/3+6r=)

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Solution for (7r-2/3)-(2/3+6r=) equation: 



(7r-2/3)-(2/3+6r=)

We move all terms to the left:

(7r-2/3)-(2/3+6r-())=0



Domain of the equation: 3+6r-())!=0

We move all terms containing r to the left, all other terms to the right

6r-())!=-3

r∈R



We add all the numbers together, and all the variables

(+7r-2/3)-(2/3+6r-())=0

We get rid of parentheses

7r-(2/3+6r-())-2/3=0

We calculate fractions


7r=0

r=0/7

r=0

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