(7t-2)(-3t+1)=3(1-3t

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Solution for (7t-2)(-3t+1)=3(1-3t equation: 



(7t-2)(-3t+1)=3(1-3t

We move all terms to the left:

(7t-2)(-3t+1)-(3(1-3t)=0

We add all the numbers together, and all the variables

(7t-2)(-3t+1)-(3(-3t+1)=0

We multiply parentheses ..

(-21t^2+7t+6t-2)-(3(-3t+1)=0



We calculate terms in parentheses: -(3(-3t+1), so:

3(-3t+1



We get rid of parentheses

-21t^2+7t+6t-(3(-3t+1)-2=0

We add all the numbers together, and all the variables

-21t^2+13t-(3(-3t+1)-2=0

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