(7t-2)+(-3t+1)=-3(1-3t)

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Solution for (7t-2)+(-3t+1)=-3(1-3t) equation: 



(7t-2)+(-3t+1)=-3(1-3t)

We move all terms to the left:

(7t-2)+(-3t+1)-(-3(1-3t))=0

We add all the numbers together, and all the variables

(7t-2)+(-3t+1)-(-3(-3t+1))=0

We get rid of parentheses

7t-3t-(-3(-3t+1))-2+1=0



We calculate terms in parentheses: -(-3(-3t+1)), so:

-3(-3t+1)

We multiply parentheses

9t-3

Back to the equation:

-(9t-3)



We add all the numbers together, and all the variables

4t-(9t-3)-1=0

We get rid of parentheses

4t-9t+3-1=0

We add all the numbers together, and all the variables

-5t+2=0

We move all terms containing t to the left, all other terms to the right

-5t=-2

t=-2/-5

t=2/5

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