(7t-2)-(3-t+1)=3(1-3t)

Solution for (7t-2)-(3-t+1)=3(1-3t) equation:

(7t-2)-(3-t+1)=3(1-3t)

We move all terms to the left:

(7t-2)-(3-t+1)-(3(1-3t))=0

We add all the numbers together, and all the variables

(7t-2)-(-1t+4)-(3(-3t+1))=0

We get rid of parentheses

7t+1t-(3(-3t+1))-2-4=0


We calculate terms in parentheses: -(3(-3t+1)), so:

3(-3t+1)

We multiply parentheses

-9t+3

Back to the equation:

-(-9t+3)


We add all the numbers together, and all the variables

8t-(-9t+3)-6=0

We get rid of parentheses

8t+9t-3-6=0

We add all the numbers together, and all the variables

17t-9=0

We move all terms containing t to the left, all other terms to the right

17t=9

t=9/17

t=9/17