(7t-2)-(3t+1)=-3+(1-3t)

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Solution for (7t-2)-(3t+1)=-3+(1-3t) equation: 



(7t-2)-(3t+1)=-3+(1-3t)

We move all terms to the left:

(7t-2)-(3t+1)-(-3+(1-3t))=0

We add all the numbers together, and all the variables

(7t-2)-(3t+1)-(-3+(-3t+1))=0

We get rid of parentheses

7t-3t-(-3+(-3t+1))-2-1=0



We calculate terms in parentheses: -(-3+(-3t+1)), so:

-3+(-3t+1)

determiningTheFunctionDomain
(-3t+1)-3

We get rid of parentheses

-3t+1-3

We add all the numbers together, and all the variables

-3t-2

Back to the equation:

-(-3t-2)



We add all the numbers together, and all the variables

4t-(-3t-2)-3=0

We get rid of parentheses

4t+3t+2-3=0

We add all the numbers together, and all the variables

7t-1=0

We move all terms containing t to the left, all other terms to the right

7t=1

t=1/7

t=1/7

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