(7t-5)=2(t+1)+2

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Solution for (7t-5)=2(t+1)+2 equation:


Simplifying
(7t + -5) = 2(t + 1) + 2

Reorder the terms:
(-5 + 7t) = 2(t + 1) + 2

Remove parenthesis around (-5 + 7t)
-5 + 7t = 2(t + 1) + 2

Reorder the terms:
-5 + 7t = 2(1 + t) + 2
-5 + 7t = (1 * 2 + t * 2) + 2
-5 + 7t = (2 + 2t) + 2

Reorder the terms:
-5 + 7t = 2 + 2 + 2t

Combine like terms: 2 + 2 = 4
-5 + 7t = 4 + 2t

Solving
-5 + 7t = 4 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-5 + 7t + -2t = 4 + 2t + -2t

Combine like terms: 7t + -2t = 5t
-5 + 5t = 4 + 2t + -2t

Combine like terms: 2t + -2t = 0
-5 + 5t = 4 + 0
-5 + 5t = 4

Add '5' to each side of the equation.
-5 + 5 + 5t = 4 + 5

Combine like terms: -5 + 5 = 0
0 + 5t = 4 + 5
5t = 4 + 5

Combine like terms: 4 + 5 = 9
5t = 9

Divide each side by '5'.
t = 1.8

Simplifying
t = 1.8

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