(7u+5)/4=(4u-9)/2+4

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Solution for (7u+5)/4=(4u-9)/2+4 equation: 



(7u+5)/4=(4u-9)/2+4

We move all terms to the left:

(7u+5)/4-((4u-9)/2+4)=0

We calculate fractions


(14u+10)/()+(-((4u-9)*4)/()=0



We calculate terms in parentheses: +(-((4u-9)*4)/(), so:

-((4u-9)*4)/(

We multiply all the terms by the denominator


-((4u-9)*4)



We calculate terms in parentheses: -((4u-9)*4), so:

(4u-9)*4

We multiply parentheses

16u-36

Back to the equation:

-(16u-36)



We get rid of parentheses

-16u+36

Back to the equation:

+(-16u+36)



We get rid of parentheses

(14u+10)/()-16u+36=0

We multiply all the terms by the denominator


(14u+10)-16u*()+36*()=0

We add all the numbers together, and all the variables

(14u+10)-16u*()=0

We get rid of parentheses

14u-16u*()+10=0

We move all terms containing u to the left, all other terms to the right

14u-16u*()=-10

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