(7u-2)/6=(4u-2)/5+3

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Solution for (7u-2)/6=(4u-2)/5+3 equation: 



(7u-2)/6=(4u-2)/5+3

We move all terms to the left:

(7u-2)/6-((4u-2)/5+3)=0

We calculate fractions


(35u-10)/()+(-((4u-2)*6)/()=0



We calculate terms in parentheses: +(-((4u-2)*6)/(), so:

-((4u-2)*6)/(

We multiply all the terms by the denominator


-((4u-2)*6)



We calculate terms in parentheses: -((4u-2)*6), so:

(4u-2)*6

We multiply parentheses

24u-12

Back to the equation:

-(24u-12)



We get rid of parentheses

-24u+12

Back to the equation:

+(-24u+12)



We get rid of parentheses

(35u-10)/()-24u+12=0

We multiply all the terms by the denominator


(35u-10)-24u*()+12*()=0

We add all the numbers together, and all the variables

(35u-10)-24u*()=0

We get rid of parentheses

35u-24u*()-10=0

We move all terms containing u to the left, all other terms to the right

35u-24u*()=10

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