(7u-2)/6=(4u-2)/5+3

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Solution for (7u-2)/6=(4u-2)/5+3 equation:



(7u-2)/6=(4u-2)/5+3
We move all terms to the left:
(7u-2)/6-((4u-2)/5+3)=0
We calculate fractions
(35u-10)/()+(-((4u-2)*6)/()=0
We calculate terms in parentheses: +(-((4u-2)*6)/(), so:
-((4u-2)*6)/(
We multiply all the terms by the denominator
-((4u-2)*6)
We calculate terms in parentheses: -((4u-2)*6), so:
(4u-2)*6
We multiply parentheses
24u-12
Back to the equation:
-(24u-12)
We get rid of parentheses
-24u+12
Back to the equation:
+(-24u+12)
We get rid of parentheses
(35u-10)/()-24u+12=0
We multiply all the terms by the denominator
(35u-10)-24u*()+12*()=0
We add all the numbers together, and all the variables
(35u-10)-24u*()=0
We get rid of parentheses
35u-24u*()-10=0
We move all terms containing u to the left, all other terms to the right
35u-24u*()=10

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