(7v-3)(9v-8)=0

Solution for (7v-3)(9v-8)=0 equation:

(7v-3)(9v-8)=0

We multiply parentheses ..

(+63v^2-56v-27v+24)=0

We get rid of parentheses

63v^2-56v-27v+24=0

We add all the numbers together, and all the variables

63v^2-83v+24=0

a = 63; b = -83; c = +24;
Δ = b2-4ac
Δ = -832-4·63·24
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-83)-29}{2*63}=\frac{54}{126}
=3/7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-83)+29}{2*63}=\frac{112}{126}
=8/9
$