(7w+4)(w+8)=0

Solution for (7w+4)(w+8)=0 equation:

(7w+4)(w+8)=0

We multiply parentheses ..

(+7w^2+56w+4w+32)=0

We get rid of parentheses

7w^2+56w+4w+32=0

We add all the numbers together, and all the variables

7w^2+60w+32=0

a = 7; b = 60; c = +32;
Δ = b2-4ac
Δ = 602-4·7·32
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-52}{2*7}=\frac{-112}{14}
=-8
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+52}{2*7}=\frac{-8}{14}
=-4/7
$