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(7x)(x-4)=90
We move all terms to the left:
(7x)(x-4)-(90)=0
We multiply parentheses
7x^2-28x-90=0
a = 7; b = -28; c = -90;
Δ = b2-4ac
Δ = -282-4·7·(-90)
Δ = 3304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3304}=\sqrt{4*826}=\sqrt{4}*\sqrt{826}=2\sqrt{826}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-2\sqrt{826}}{2*7}=\frac{28-2\sqrt{826}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+2\sqrt{826}}{2*7}=\frac{28+2\sqrt{826}}{14} $
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