(7x)/(59x+36)=(1)/(x)

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Solution for (7x)/(59x+36)=(1)/(x) equation:


D( x )

x = 0

59*x+36 = 0

x = 0

x = 0

59*x+36 = 0

59*x+36 = 0

59*x+36 = 0 // - 36

59*x = -36 // : 59

x = -36/59

x in (-oo:-36/59) U (-36/59:0) U (0:+oo)

(7*x)/(59*x+36) = 1/x // - 1/x

(7*x)/(59*x+36)-(1/x) = 0

(7*x)/(59*x+36)-x^-1 = 0

(7*x)/(59*x+36)-1/x = 0

(7*x*x)/(x*(59*x+36))+(-1*(59*x+36))/(x*(59*x+36)) = 0

7*x*x-1*(59*x+36) = 0

7*x^2-59*x-36 = 0

7*x^2-59*x-36 = 0

7*x^2-59*x-36 = 0

DELTA = (-59)^2-(-36*4*7)

DELTA = 4489

DELTA > 0

x = (4489^(1/2)+59)/(2*7) or x = (59-4489^(1/2))/(2*7)

x = 9 or x = -4/7

(x+4/7)*(x-9) = 0

((x+4/7)*(x-9))/(x*(59*x+36)) = 0

((x+4/7)*(x-9))/(x*(59*x+36)) = 0 // * x*(59*x+36)

(x+4/7)*(x-9) = 0

( x+4/7 )

x+4/7 = 0 // - 4/7

x = -4/7

( x-9 )

x-9 = 0 // + 9

x = 9

x in { -4/7, 9 }

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